5[y-2]-2=2[y+1]-5

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Solution for 5[y-2]-2=2[y+1]-5 equation:


Simplifying
5[y + -2] + -2 = 2[y + 1] + -5

Reorder the terms:
5[-2 + y] + -2 = 2[y + 1] + -5
[-2 * 5 + y * 5] + -2 = 2[y + 1] + -5
[-10 + 5y] + -2 = 2[y + 1] + -5

Reorder the terms:
-10 + -2 + 5y = 2[y + 1] + -5

Combine like terms: -10 + -2 = -12
-12 + 5y = 2[y + 1] + -5

Reorder the terms:
-12 + 5y = 2[1 + y] + -5
-12 + 5y = [1 * 2 + y * 2] + -5
-12 + 5y = [2 + 2y] + -5

Reorder the terms:
-12 + 5y = 2 + -5 + 2y

Combine like terms: 2 + -5 = -3
-12 + 5y = -3 + 2y

Solving
-12 + 5y = -3 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.
-12 + 5y + -2y = -3 + 2y + -2y

Combine like terms: 5y + -2y = 3y
-12 + 3y = -3 + 2y + -2y

Combine like terms: 2y + -2y = 0
-12 + 3y = -3 + 0
-12 + 3y = -3

Add '12' to each side of the equation.
-12 + 12 + 3y = -3 + 12

Combine like terms: -12 + 12 = 0
0 + 3y = -3 + 12
3y = -3 + 12

Combine like terms: -3 + 12 = 9
3y = 9

Divide each side by '3'.
y = 3

Simplifying
y = 3

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